If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+3-13x=0
a = 12; b = -13; c = +3;
Δ = b2-4ac
Δ = -132-4·12·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*12}=\frac{8}{24} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*12}=\frac{18}{24} =3/4 $
| x+9/3=10 | | 3x-30=3-(5x-2) | | 294=207-v | | -3c+10=40 | | 60-x=173 | | 3d=7+5 | | 29+x/4=3 | | (16+x)6=1,038 | | 235=178-y | | z+12=3z+2 | | a-5=2a-21 | | x+5.50=108.50 | | -x²+4=0 | | 2c=c+47 | | 2s=s+51 | | 4w=w+57 | | 7u=u+84 | | 35=3u-9 | | 8(11+x)=24 | | -70=2v+8v | | 35=7(v+12) | | 2(x-4)-14=-34 | | -4(4+b)=-20 | | 3x=5+2x= | | 100=10(11+y) | | 3x+4(2x-8)=12 | | (2/5x)+(5x+5/5x)=2 | | 2/5x+5x+5/5x=2 | | 4x+6(3x+2)=56 | | 2=2+d/5 | | 2x+3(18x-4)=156 | | -2=-6(6+x)+10 |